# Line slope calculator 5x+6y=80

**Straight line given by points A[4; 10] and B[10; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.8333x+13.3333

**Canonical form of the line equation:**5x+6y-80 = 0

**Parametric form of the line equation:**

x = 6t+4

y = -5t+10 ; t ∈ R

**Slope:**m = -0.8333

**Slope angle of line: φ =**-39°48'20″ = -0.6947 rad

**X intercept:**x

_{0}= 16

**Y intercept:**y

_{0}= q = 13.3333

**Distance line from the origin:**d

_{0}= 10.243

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(6; -5)

**Normal vector: n =**(5; 6)

**Midpoint of the segment AB: M =**[7; 7.5]

**Perpendicular Bisector equation:**6x-5y-4.5 = 0

**Vector OA = (4; 10) ; |OA| = 10.7703**

**Vector OB = (10; 5) ; |OB| = 11.1803**

**Scalar product OA .OB = 90**

**Angle ∠ AOB = 41°38'1″ = 0.7266 rad**